What are the solutions to the equation 5q^2+q-1=0 ?

The solutions to the equation 5q^2+q-1=0 are q=(-1+sqrt(21))/(10),q=(-1-sqrt(21))/(10)

Find the zeros of 5q^2+q-1=0

The zeros of 5q^2+q-1=0 are q=(-1+sqrt(21))/(10),q=(-1-sqrt(21))/(10)

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5 q^{2} + q - 1 = 0

q = \frac{- 1 + 21}{10}, q = \frac{- 1 - 21}{10}

Decimal Notation

q = 0.35825 \dots, q = - 0.55825 \dots

Solution steps

5 q^{2} + q - 1 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 ( - 1 )}{2 \cdot 5}

1^{2} - 4 \cdot 5 (- 1) = 21

q_{1, 2} = \frac{- 1 \pm 21}{2 \cdot 5}

Separate the solutions

q_{1} = \frac{- 1 + 21}{2 \cdot 5}, q_{2} = \frac{- 1 - 21}{2 \cdot 5}

q = \frac{- 1 + 21}{2 \cdot 5} : \frac{- 1 + 21}{10}

q = \frac{- 1 - 21}{2 \cdot 5} : \frac{- 1 - 21}{10}

The solutions to the quadratic equation are:

q = \frac{- 1 + 21}{10}, q = \frac{- 1 - 21}{10}

x^{2} - 9 x - 8 = 0

y^{2} - 6 y + 7 = 0

2 q^{2} - 16 q = - 73

4 m^{2} - 5 m - 1 = 2 m

18 x^{2} - 24 x = 0

What are the solutions to the equation 5q^2+q-1=0 ?
The solutions to the equation 5q^2+q-1=0 are q=(-1+sqrt(21))/(10),q=(-1-sqrt(21))/(10)
Find the zeros of 5q^2+q-1=0
The zeros of 5q^2+q-1=0 are q=(-1+sqrt(21))/(10),q=(-1-sqrt(21))/(10)