What are the solutions to the equation x^2+16x+55=0 ?

The solutions to the equation x^2+16x+55=0 are x=-5,x=-11

Find the zeros of x^2+16x+55=0

The zeros of x^2+16x+55=0 are x=-5,x=-11

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x^{2} + 16 x + 55 = 0

x = - 5, x = - 11

Solution steps

x^{2} + 16 x + 55 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 55}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 55 = 6

x_{1, 2} = \frac{- 16 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 6}{2 \cdot 1}, x_{2} = \frac{- 16 - 6}{2 \cdot 1}

x = \frac{- 16 + 6}{2 \cdot 1} : - 5

x = \frac{- 16 - 6}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = - 5, x = - 11

2 - y = - 4

4 x^{4} + 4 x^{3} + x^{2}

\frac{2 ^{- 3} x ^{0}}{y ^{- 4}}

4 (x + 3) = 6 x + 3 x + 7

x^{2} + 10 x + 41 = 0

What are the solutions to the equation x^2+16x+55=0 ?
The solutions to the equation x^2+16x+55=0 are x=-5,x=-11
Find the zeros of x^2+16x+55=0
The zeros of x^2+16x+55=0 are x=-5,x=-11