What are the solutions to the equation x^2+15x+15=2+x ?

The solutions to the equation x^2+15x+15=2+x are x=-1,x=-13

Find the zeros of x^2+15x+15=2+x

The zeros of x^2+15x+15=2+x are x=-1,x=-13

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x^{2} + 15 x + 15 = 2 + x

x = - 1, x = - 13

Solution steps

x^{2} + 15 x + 15 = 2 + x

Move

x

to the left side

x^{2} + 14 x + 15 = 2

Move

2

to the left side

x^{2} + 14 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 13 = 12

x_{1, 2} = \frac{- 14 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 12}{2 \cdot 1}, x_{2} = \frac{- 14 - 12}{2 \cdot 1}

x = \frac{- 14 + 12}{2 \cdot 1} : - 1

x = \frac{- 14 - 12}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = - 1, x = - 13

x^{2} - 75 = 0

k, k 0.8 k + 2 m = 3 m + k

y^{2} = 8

2 m x^{2} - (m - 4) x - 2 = 0

x, 5 x^{2} + 4 x y + 8 y^{2} - 40 x - 52 y + 116 = 0

What are the solutions to the equation x^2+15x+15=2+x ?
The solutions to the equation x^2+15x+15=2+x are x=-1,x=-13
Find the zeros of x^2+15x+15=2+x
The zeros of x^2+15x+15=2+x are x=-1,x=-13