What are the solutions to the equation completesquare-x^2+4x ?

The solutions to the equation completesquare-x^2+4x are -(x-2)^2+4

Find the zeros of completesquare-x^2+4x

The zeros of completesquare-x^2+4x are -(x-2)^2+4

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complete the square

- x^{2} + 4 x

- (x - 2)^{2} + 4

Solution steps

- x^{2} + 4 x

Write

- x^{2} + 4 x

in the form:

x^{2} + 2 a x + a^{2}

Factor out

- 1

- (x^{2} - 4 x)

2 a = - 4 : a = - 2

Add and subtract

(- 2)^{2}

- (x^{2} - 4 x + (- 2)^{2} - (- 2)^{2})

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} - 4 x + (- 2)^{2} = (x - 2)^{2}

- ((x - 2)^{2} - (- 2)^{2})

Simplify

- (x - 2)^{2} + 4

y, x = 2 y - y^{2}

x^{2} + (x + 1)^{2} = (x - 1) (x + 2)

4 x^{2} - 4 x - 11 = - 8

4 x^{2} - 4 x + 2 = 0

x^{2} - 12 x - 160 = 0

What are the solutions to the equation completesquare-x^2+4x ?
The solutions to the equation completesquare-x^2+4x are -(x-2)^2+4
Find the zeros of completesquare-x^2+4x
The zeros of completesquare-x^2+4x are -(x-2)^2+4