What are the solutions to the equation 3m^2+15m+21=4 ?

The solutions to the equation 3m^2+15m+21=4 are m=(-15+sqrt(21))/6 ,m=(-15-sqrt(21))/6

Find the zeros of 3m^2+15m+21=4

The zeros of 3m^2+15m+21=4 are m=(-15+sqrt(21))/6 ,m=(-15-sqrt(21))/6

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3 m^{2} + 15 m + 21 = 4

m = \frac{- 15 + 21}{6}, m = \frac{- 15 - 21}{6}

Decimal Notation

m = - 1.73623 \dots, m = - 3.26376 \dots

Solution steps

3 m^{2} + 15 m + 21 = 4

Move

4

to the left side

3 m^{2} + 15 m + 17 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 3 \cdot 17}{2 \cdot 3}

1 5^{2} - 4 \cdot 3 \cdot 17 = 21

m_{1, 2} = \frac{- 15 \pm 21}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- 15 + 21}{2 \cdot 3}, m_{2} = \frac{- 15 - 21}{2 \cdot 3}

m = \frac{- 15 + 21}{2 \cdot 3} : \frac{- 15 + 21}{6}

m = \frac{- 15 - 21}{2 \cdot 3} : \frac{- 15 - 21}{6}

The solutions to the quadratic equation are:

m = \frac{- 15 + 21}{6}, m = \frac{- 15 - 21}{6}

7 x^{2} = 4 x - 1

(5 x + 6) (4 x - 5) = (5 x + 6) (x + 10) - 42 x

x^{2} - 6 x - 135 = 0

x^{2} + 16 x + 89 = 0

4 x^{2} - 4 x - 2 = 0

What are the solutions to the equation 3m^2+15m+21=4 ?
The solutions to the equation 3m^2+15m+21=4 are m=(-15+sqrt(21))/6 ,m=(-15-sqrt(21))/6
Find the zeros of 3m^2+15m+21=4
The zeros of 3m^2+15m+21=4 are m=(-15+sqrt(21))/6 ,m=(-15-sqrt(21))/6