What are the solutions to the equation 9r^2+21r+9=-r^2 ?

The solutions to the equation 9r^2+21r+9=-r^2 are r=-3/5 ,r=-3/2

Find the zeros of 9r^2+21r+9=-r^2

The zeros of 9r^2+21r+9=-r^2 are r=-3/5 ,r=-3/2

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9 r^{2} + 21 r + 9 = - r^{2}

r = - \frac{3}{5}, r = - \frac{3}{2}

Decimal Notation

r = - 0.6, r = - 1.5

Solution steps

9 r^{2} + 21 r + 9 = - r^{2}

Move

r^{2}

to the left side

10 r^{2} + 21 r + 9 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 10 \cdot 9}{2 \cdot 10}

2 1^{2} - 4 \cdot 10 \cdot 9 = 9

r_{1, 2} = \frac{- 21 \pm 9}{2 \cdot 10}

Separate the solutions

r_{1} = \frac{- 21 + 9}{2 \cdot 10}, r_{2} = \frac{- 21 - 9}{2 \cdot 10}

r = \frac{- 21 + 9}{2 \cdot 10} : - \frac{3}{5}

r = \frac{- 21 - 9}{2 \cdot 10} : - \frac{3}{2}

The solutions to the quadratic equation are:

r = - \frac{3}{5}, r = - \frac{3}{2}

x^{2} - 10 x + 13 = 0

(x + 6) (x - 2) = 9

100 = x^{2}

4 x^{2} - 4 x = 1

m^{2} + 11 m + 13 = 0

What are the solutions to the equation 9r^2+21r+9=-r^2 ?
The solutions to the equation 9r^2+21r+9=-r^2 are r=-3/5 ,r=-3/2
Find the zeros of 9r^2+21r+9=-r^2
The zeros of 9r^2+21r+9=-r^2 are r=-3/5 ,r=-3/2