What are the solutions to the equation 2(x+2)^2-(x-1)^2=2x+7 ?

The solutions to the equation 2(x+2)^2-(x-1)^2=2x+7 are x=0,x=-8

Find the zeros of 2(x+2)^2-(x-1)^2=2x+7

The zeros of 2(x+2)^2-(x-1)^2=2x+7 are x=0,x=-8

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2 (x + 2)^{2} - (x - 1)^{2} = 2 x + 7

x = 0, x = - 8

Solution steps

2 (x + 2)^{2} - (x - 1)^{2} = 2 x + 7

Expand

2 (x + 2)^{2} - (x - 1)^{2} : x^{2} + 10 x + 7

x^{2} + 10 x + 7 = 2 x + 7

Move

7

to the left side

x^{2} + 10 x = 2 x

Move

2 x

to the left side

x^{2} + 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 8}{2 \cdot 1}, x_{2} = \frac{- 8 - 8}{2 \cdot 1}

x = \frac{- 8 + 8}{2 \cdot 1} : 0

x = \frac{- 8 - 8}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 0, x = - 8

x^{2} + 18 x + 326 = 0

2 x^{2} + 9 x = - 7

5 x^{2} - 4 x - 7 = 1 - x

x, x^{2} - x - 2 = 0

u^{2} - 17 u + 16 = 0

What are the solutions to the equation 2(x+2)^2-(x-1)^2=2x+7 ?
The solutions to the equation 2(x+2)^2-(x-1)^2=2x+7 are x=0,x=-8
Find the zeros of 2(x+2)^2-(x-1)^2=2x+7
The zeros of 2(x+2)^2-(x-1)^2=2x+7 are x=0,x=-8