What are the solutions to the equation 5u^2=20u-15 ?

The solutions to the equation 5u^2=20u-15 are u=3,u=1

Find the zeros of 5u^2=20u-15

The zeros of 5u^2=20u-15 are u=3,u=1

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5 u^{2} = 20 u - 15

u = 3, u = 1

Solution steps

5 u^{2} = 20 u - 15

Move

15

to the left side

5 u^{2} + 15 = 20 u

Move

20 u

to the left side

5 u^{2} + 15 - 20 u = 0

Write in the standard form

a x^{2} + b x + c = 0

5 u^{2} - 20 u + 15 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 5 \cdot 15}{2 \cdot 5}

(- 20)^{2} - 4 \cdot 5 \cdot 15 = 10

u_{1, 2} = \frac{- ( - 20 ) \pm 10}{2 \cdot 5}

Separate the solutions

u_{1} = \frac{- ( - 20 ) + 10}{2 \cdot 5}, u_{2} = \frac{- ( - 20 ) - 10}{2 \cdot 5}

u = \frac{- ( - 20 ) + 10}{2 \cdot 5} : 3

u = \frac{- ( - 20 ) - 10}{2 \cdot 5} : 1

The solutions to the quadratic equation are:

u = 3, u = 1

x^{2} + 5 x + 4 \leq 0

85

6 x^{2} + 6 = 12 x + 18

4 x^{3} - 20 x^{2} + 24 x

2 x + 9 > 11

What are the solutions to the equation 5u^2=20u-15 ?
The solutions to the equation 5u^2=20u-15 are u=3,u=1
Find the zeros of 5u^2=20u-15
The zeros of 5u^2=20u-15 are u=3,u=1