What are the solutions to the equation 4(3x+4)^2-40=-24 ?

The solutions to the equation 4(3x+4)^2-40=-24 are x=-2/3 ,x=-2

Find the zeros of 4(3x+4)^2-40=-24

The zeros of 4(3x+4)^2-40=-24 are x=-2/3 ,x=-2

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4 (3 x + 4)^{2} - 40 = - 24

x = - \frac{2}{3}, x = - 2

Decimal Notation

x = - 0.66666 \dots, x = - 2

Solution steps

4 (3 x + 4)^{2} - 40 = - 24

Move

40

to the right side

4 (3 x + 4)^{2} = 16

Divide both sides by

4

(3 x + 4)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 4 = 4 : x = - \frac{2}{3}

Solve

3 x + 4 = - 4 : x = - 2

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = - 2

a^{2} + 6 a + 4 = 0

25 x^{2} = 20 x - 4

- 19 = - 3 - n^{2}

x^{2} - 4 x = - 4 x + 4

3 t^{2} - 6 t = 0

What are the solutions to the equation 4(3x+4)^2-40=-24 ?
The solutions to the equation 4(3x+4)^2-40=-24 are x=-2/3 ,x=-2
Find the zeros of 4(3x+4)^2-40=-24
The zeros of 4(3x+4)^2-40=-24 are x=-2/3 ,x=-2