What are the solutions to the equation x^2+3x-13=0 ?

The solutions to the equation x^2+3x-13=0 are x=(-3+sqrt(61))/2 ,x=(-3-sqrt(61))/2

Find the zeros of x^2+3x-13=0

The zeros of x^2+3x-13=0 are x=(-3+sqrt(61))/2 ,x=(-3-sqrt(61))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 3 x - 13 = 0

x = \frac{- 3 + 61}{2}, x = \frac{- 3 - 61}{2}

Decimal Notation

x = 2.40512 \dots, x = - 5.40512 \dots

Solution steps

x^{2} + 3 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 13 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 13) = 61

x_{1, 2} = \frac{- 3 \pm 61}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 61}{2 \cdot 1}, x_{2} = \frac{- 3 - 61}{2 \cdot 1}

x = \frac{- 3 + 61}{2 \cdot 1} : \frac{- 3 + 61}{2}

x = \frac{- 3 - 61}{2 \cdot 1} : \frac{- 3 - 61}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 61}{2}, x = \frac{- 3 - 61}{2}

x^{2} = c

x^{2} + 5 x + 8

6 x^{2} - 4 x - 2 = 0

4 w^{2} + 12 w + 9 = 49

1 = 4 x^{2} + 3 x

What are the solutions to the equation x^2+3x-13=0 ?
The solutions to the equation x^2+3x-13=0 are x=(-3+sqrt(61))/2 ,x=(-3-sqrt(61))/2
Find the zeros of x^2+3x-13=0
The zeros of x^2+3x-13=0 are x=(-3+sqrt(61))/2 ,x=(-3-sqrt(61))/2