What are the solutions to the equation -4m^2+2m-11=-5m^2 ?

The solutions to the equation -4m^2+2m-11=-5m^2 are m=-1+2sqrt(3),m=-1-2sqrt(3)

Find the zeros of -4m^2+2m-11=-5m^2

The zeros of -4m^2+2m-11=-5m^2 are m=-1+2sqrt(3),m=-1-2sqrt(3)

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- 4 m^{2} + 2 m - 11 = - 5 m^{2}

m = - 1 + 23, m = - 1 - 23

Decimal Notation

m = 2.46410 \dots, m = - 4.46410 \dots

Solution steps

- 4 m^{2} + 2 m - 11 = - 5 m^{2}

Move

5 m^{2}

to the left side

m^{2} + 2 m - 11 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 11) = 43

m_{1, 2} = \frac{- 2 \pm 4 3}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 2 + 4 3}{2 \cdot 1}, m_{2} = \frac{- 2 - 4 3}{2 \cdot 1}

m = \frac{- 2 + 4 3}{2 \cdot 1} : - 1 + 23

m = \frac{- 2 - 4 3}{2 \cdot 1} : - 1 - 23

The solutions to the quadratic equation are:

m = - 1 + 23, m = - 1 - 23

- 12 x^{2} - 92 x - 56 = 0

2 x^{2} - 7 x + 12 = 0

3 x^{2} - (2 m + 12) x + 216 = 0

x^{2} - \frac{1}{2} x - \frac{1}{2} = 0

y^{2} - 4 y - 21 = 0

What are the solutions to the equation -4m^2+2m-11=-5m^2 ?
The solutions to the equation -4m^2+2m-11=-5m^2 are m=-1+2sqrt(3),m=-1-2sqrt(3)
Find the zeros of -4m^2+2m-11=-5m^2
The zeros of -4m^2+2m-11=-5m^2 are m=-1+2sqrt(3),m=-1-2sqrt(3)