What are the solutions to the equation -x^2+600x-90=0 ?

The solutions to the equation -x^2+600x-90=0 are x=3(100-3sqrt(1110)),x=3(100+3sqrt(1110))

Find the zeros of -x^2+600x-90=0

The zeros of -x^2+600x-90=0 are x=3(100-3sqrt(1110)),x=3(100+3sqrt(1110))

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- x^{2} + 600 x - 90 = 0

x = 3 (100 - 31110), x = 3 (100 + 31110)

Decimal Notation

x = 0.15003 \dots, x = 599.84996 \dots

Solution steps

- x^{2} + 600 x - 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 600 \pm 60 0 ^{2} - 4 ( - 1 ) ( - 90 )}{2 ( - 1 )}

60 0^{2} - 4 (- 1) (- 90) = 181110

x_{1, 2} = \frac{- 600 \pm 18 1110}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 600 + 18 1110}{2 ( - 1 )}, x_{2} = \frac{- 600 - 18 1110}{2 ( - 1 )}

x = \frac{- 600 + 18 1110}{2 ( - 1 )} : 3 (100 - 31110)

x = \frac{- 600 - 18 1110}{2 ( - 1 )} : 3 (100 + 31110)

The solutions to the quadratic equation are:

x = 3 (100 - 31110), x = 3 (100 + 31110)

- 3 x^{2} - 54 x - 96 = 0

3 x^{2} = 30 x

2 x^{2} - x - 3 = 0

4 x^{2} - 16 x + 17 = 0

x^{2} + 45 = - 14 x

What are the solutions to the equation -x^2+600x-90=0 ?
The solutions to the equation -x^2+600x-90=0 are x=3(100-3sqrt(1110)),x=3(100+3sqrt(1110))
Find the zeros of -x^2+600x-90=0
The zeros of -x^2+600x-90=0 are x=3(100-3sqrt(1110)),x=3(100+3sqrt(1110))