What are the solutions to the equation 3n^2+16n+15=1 ?

The solutions to the equation 3n^2+16n+15=1 are n=(-8+sqrt(22))/3 ,n=-(8+sqrt(22))/3

Find the zeros of 3n^2+16n+15=1

The zeros of 3n^2+16n+15=1 are n=(-8+sqrt(22))/3 ,n=-(8+sqrt(22))/3

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3 n^{2} + 16 n + 15 = 1

n = \frac{- 8 + 22}{3}, n = - \frac{8 + 22}{3}

Decimal Notation

n = - 1.10319 \dots, n = - 4.23013 \dots

Solution steps

3 n^{2} + 16 n + 15 = 1

Move

1

to the left side

3 n^{2} + 16 n + 14 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 3 \cdot 14}{2 \cdot 3}

1 6^{2} - 4 \cdot 3 \cdot 14 = 222

n_{1, 2} = \frac{- 16 \pm 2 22}{2 \cdot 3}

Separate the solutions

n_{1} = \frac{- 16 + 2 22}{2 \cdot 3}, n_{2} = \frac{- 16 - 2 22}{2 \cdot 3}

n = \frac{- 16 + 2 22}{2 \cdot 3} : \frac{- 8 + 22}{3}

n = \frac{- 16 - 2 22}{2 \cdot 3} : - \frac{8 + 22}{3}

The solutions to the quadratic equation are:

n = \frac{- 8 + 22}{3}, n = - \frac{8 + 22}{3}

4 x^{2} + 5 = - 12 x

x^{2} + 8 x + 19 = 6

2 x^{2} + 20 = 8

0 = x^{2} - 4 x + 5

t, h = \frac{1}{2} g t^{2} + v t

What are the solutions to the equation 3n^2+16n+15=1 ?
The solutions to the equation 3n^2+16n+15=1 are n=(-8+sqrt(22))/3 ,n=-(8+sqrt(22))/3
Find the zeros of 3n^2+16n+15=1
The zeros of 3n^2+16n+15=1 are n=(-8+sqrt(22))/3 ,n=-(8+sqrt(22))/3