What are the solutions to the equation 3w^2+15w+12=w ?

The solutions to the equation 3w^2+15w+12=w are w=(-7+sqrt(13))/3 ,w=-(7+sqrt(13))/3

Find the zeros of 3w^2+15w+12=w

The zeros of 3w^2+15w+12=w are w=(-7+sqrt(13))/3 ,w=-(7+sqrt(13))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 w^{2} + 15 w + 12 = w

w = \frac{- 7 + 13}{3}, w = - \frac{7 + 13}{3}

Decimal Notation

w = - 1.13148 \dots, w = - 3.53518 \dots

Solution steps

3 w^{2} + 15 w + 12 = w

Move

w

to the left side

3 w^{2} + 14 w + 12 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

1 4^{2} - 4 \cdot 3 \cdot 12 = 213

w_{1, 2} = \frac{- 14 \pm 2 13}{2 \cdot 3}

Separate the solutions

w_{1} = \frac{- 14 + 2 13}{2 \cdot 3}, w_{2} = \frac{- 14 - 2 13}{2 \cdot 3}

w = \frac{- 14 + 2 13}{2 \cdot 3} : \frac{- 7 + 13}{3}

w = \frac{- 14 - 2 13}{2 \cdot 3} : - \frac{7 + 13}{3}

The solutions to the quadratic equation are:

w = \frac{- 7 + 13}{3}, w = - \frac{7 + 13}{3}

3 y^{2} + 6 y - 9 = 0

x^{2} + x + 1 = 0

y^{2} - \frac{1}{3} a y = 0

- 2 x^{2} - 8 = 0

\frac{1}{2} x + 5 x^{2} - 6 x = \frac{1}{2} x^{2} + x

What are the solutions to the equation 3w^2+15w+12=w ?
The solutions to the equation 3w^2+15w+12=w are w=(-7+sqrt(13))/3 ,w=-(7+sqrt(13))/3
Find the zeros of 3w^2+15w+12=w
The zeros of 3w^2+15w+12=w are w=(-7+sqrt(13))/3 ,w=-(7+sqrt(13))/3