What are the solutions to the equation 2w^2-4w-9=0 ?

The solutions to the equation 2w^2-4w-9=0 are w=(2+sqrt(22))/2 ,w=(2-sqrt(22))/2

Find the zeros of 2w^2-4w-9=0

The zeros of 2w^2-4w-9=0 are w=(2+sqrt(22))/2 ,w=(2-sqrt(22))/2

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2 w^{2} - 4 w - 9 = 0

w = \frac{2 + 22}{2}, w = \frac{2 - 22}{2}

Decimal Notation

w = 3.34520 \dots, w = - 1.34520 \dots

Solution steps

2 w^{2} - 4 w - 9 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 9) = 222

w_{1, 2} = \frac{- ( - 4 ) \pm 2 22}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 4 ) + 2 22}{2 \cdot 2}, w_{2} = \frac{- ( - 4 ) - 2 22}{2 \cdot 2}

w = \frac{- ( - 4 ) + 2 22}{2 \cdot 2} : \frac{2 + 22}{2}

w = \frac{- ( - 4 ) - 2 22}{2 \cdot 2} : \frac{2 - 22}{2}

The solutions to the quadratic equation are:

w = \frac{2 + 22}{2}, w = \frac{2 - 22}{2}

- 2 x^{2} + 4 x - 8 = 0

x^{2} = 8^{2} + 1 5^{2}

6 x^{2} + 6 = 0

3 x^{2} + 9 x - 30 = 0

2 x^{2} = 22 x - 60

What are the solutions to the equation 2w^2-4w-9=0 ?
The solutions to the equation 2w^2-4w-9=0 are w=(2+sqrt(22))/2 ,w=(2-sqrt(22))/2
Find the zeros of 2w^2-4w-9=0
The zeros of 2w^2-4w-9=0 are w=(2+sqrt(22))/2 ,w=(2-sqrt(22))/2