What are the solutions to the equation 3(5x+4)^2-81=0 ?

The solutions to the equation 3(5x+4)^2-81=0 are x=(3sqrt(3)-4)/5 ,x=(-3sqrt(3)-4)/5

Find the zeros of 3(5x+4)^2-81=0

The zeros of 3(5x+4)^2-81=0 are x=(3sqrt(3)-4)/5 ,x=(-3sqrt(3)-4)/5

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3 (5 x + 4)^{2} - 81 = 0

x = \frac{3 3 - 4}{5}, x = \frac{- 3 3 - 4}{5}

Decimal Notation

x = 0.23923 \dots, x = - 1.83923 \dots

Solution steps

3 (5 x + 4)^{2} - 81 = 0

Move

81

to the right side

3 (5 x + 4)^{2} = 81

Divide both sides by

3

(5 x + 4)^{2} = 27

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 4 = 27 : x = \frac{3 3 - 4}{5}

Solve

5 x + 4 = - 27 : x = \frac{- 3 3 - 4}{5}

The solutions to the quadratic equation are:

x = \frac{3 3 - 4}{5}, x = \frac{- 3 3 - 4}{5}

x^{2} + 10 x - 2 = 0

x^{2} - 6 x + 9 = 4

x^{2} + 11 x

x^{2} - 5 = 11

6^{2} + 6^{2} = c^{2}

What are the solutions to the equation 3(5x+4)^2-81=0 ?
The solutions to the equation 3(5x+4)^2-81=0 are x=(3sqrt(3)-4)/5 ,x=(-3sqrt(3)-4)/5
Find the zeros of 3(5x+4)^2-81=0
The zeros of 3(5x+4)^2-81=0 are x=(3sqrt(3)-4)/5 ,x=(-3sqrt(3)-4)/5