What are the solutions to the equation z^2-16z+61=2z-20 ?

The solutions to the equation z^2-16z+61=2z-20 are z=9

Find the zeros of z^2-16z+61=2z-20

The zeros of z^2-16z+61=2z-20 are z=9

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z^{2} - 16 z + 61 = 2 z - 20

z = 9

Solution steps

z^{2} - 16 z + 61 = 2 z - 20

Move

20

to the left side

z^{2} - 16 z + 81 = 2 z

Move

2 z

to the left side

z^{2} - 18 z + 81 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 81}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 81 = 0

z_{1, 2} = \frac{- ( - 18 ) \pm 0}{2 \cdot 1}

z = \frac{- ( - 18 )}{2 \cdot 1}

\frac{- ( - 18 )}{2 \cdot 1} = 9

z = 9

The solution to the quadratic equation is:

z = 9

2 x^{2} - 16 x - 18 = 0

2 x^{2} - 20 x + 18 = 0

3 x^{2} - 16 x + 20 = 0

9 x^{2} = 24 x - 19

x^{2} - 77 = 4

What are the solutions to the equation z^2-16z+61=2z-20 ?
The solutions to the equation z^2-16z+61=2z-20 are z=9
Find the zeros of z^2-16z+61=2z-20
The zeros of z^2-16z+61=2z-20 are z=9