What are the solutions to the equation -3x^2-5x+2=0 ?

The solutions to the equation -3x^2-5x+2=0 are x=-2,x= 1/3

Find the zeros of -3x^2-5x+2=0

The zeros of -3x^2-5x+2=0 are x=-2,x= 1/3

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- 3 x^{2} - 5 x + 2 = 0

x = - 2, x = \frac{1}{3}

Decimal Notation

x = - 2, x = 0.33333 \dots

Solution steps

- 3 x^{2} - 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 3 ) \cdot 2}{2 ( - 3 )}

(- 5)^{2} - 4 (- 3) \cdot 2 = 7

x_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7}{2 ( - 3 )}, x_{2} = \frac{- ( - 5 ) - 7}{2 ( - 3 )}

x = \frac{- ( - 5 ) + 7}{2 ( - 3 )} : - 2

x = \frac{- ( - 5 ) - 7}{2 ( - 3 )} : \frac{1}{3}

The solutions to the quadratic equation are:

x = - 2, x = \frac{1}{3}

x^{2} + 8 x + 208 = 0

m^{2} + 5 m + 4 = 0

- 16 t^{2} + 48 t + 160 = 0

0 = 4 x^{2}

2 b^{2} + 6 b - 1 = 2

What are the solutions to the equation -3x^2-5x+2=0 ?
The solutions to the equation -3x^2-5x+2=0 are x=-2,x= 1/3
Find the zeros of -3x^2-5x+2=0
The zeros of -3x^2-5x+2=0 are x=-2,x= 1/3