What are the solutions to the equation q^2+6q-18=-5 ?

The solutions to the equation q^2+6q-18=-5 are q=-3+sqrt(22),q=-3-sqrt(22)

Find the zeros of q^2+6q-18=-5

The zeros of q^2+6q-18=-5 are q=-3+sqrt(22),q=-3-sqrt(22)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

q^{2} + 6 q - 18 = - 5

q = - 3 + 22, q = - 3 - 22

Decimal Notation

q = 1.69041 \dots, q = - 7.69041 \dots

Solution steps

q^{2} + 6 q - 18 = - 5

Move

5

to the left side

q^{2} + 6 q - 13 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 13 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 13) = 222

q_{1, 2} = \frac{- 6 \pm 2 22}{2 \cdot 1}

Separate the solutions

q_{1} = \frac{- 6 + 2 22}{2 \cdot 1}, q_{2} = \frac{- 6 - 2 22}{2 \cdot 1}

q = \frac{- 6 + 2 22}{2 \cdot 1} : - 3 + 22

q = \frac{- 6 - 2 22}{2 \cdot 1} : - 3 - 22

The solutions to the quadratic equation are:

q = - 3 + 22, q = - 3 - 22

3 x^{2} + 18 x + 23 = 0

y, y^{2} = x^{4} - x^{6}

1 7^{2} = x^{2} + 8^{2}

y^{2} + 4 y

y^{2} - 4 y

What are the solutions to the equation q^2+6q-18=-5 ?
The solutions to the equation q^2+6q-18=-5 are q=-3+sqrt(22),q=-3-sqrt(22)
Find the zeros of q^2+6q-18=-5
The zeros of q^2+6q-18=-5 are q=-3+sqrt(22),q=-3-sqrt(22)