What are the solutions to the equation completesquare x^2-4x+8 ?

The solutions to the equation completesquare x^2-4x+8 are (x-2)^2+4

Find the zeros of completesquare x^2-4x+8

The zeros of completesquare x^2-4x+8 are (x-2)^2+4

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complete the square

x^{2} - 4 x + 8

(x - 2)^{2} + 4

Solution steps

x^{2} - 4 x + 8

Write

x^{2} - 4 x + 8

in the form:

x^{2} + 2 a x + a^{2}

2 a = - 4 : a = - 2

Add and subtract

(- 2)^{2}

x^{2} - 4 x + 8 + (- 2)^{2} - (- 2)^{2}

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} - 4 x + (- 2)^{2} = (x - 2)^{2}

(x - 2)^{2} + 8 - (- 2)^{2}

Simplify

(x - 2)^{2} + 4

x^{2} - 4 x + 1

x, x^{2} + x y - y^{2} = 4

- 5 (x + 4) (3 x - 7) = - (x + 4) 10

4 v^{2} + 7 v - 7 = 0

12 x - 3 x^{2} = 0

What are the solutions to the equation completesquare x^2-4x+8 ?
The solutions to the equation completesquare x^2-4x+8 are (x-2)^2+4
Find the zeros of completesquare x^2-4x+8
The zeros of completesquare x^2-4x+8 are (x-2)^2+4