What are the solutions to the equation a^2-3a+2=0 ?

The solutions to the equation a^2-3a+2=0 are a=2,a=1

Find the zeros of a^2-3a+2=0

The zeros of a^2-3a+2=0 are a=2,a=1

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a^{2} - 3 a + 2 = 0

a = 2, a = 1

Solution steps

a^{2} - 3 a + 2 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 2 = 1

a_{1, 2} = \frac{- ( - 3 ) \pm 1}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 3 ) + 1}{2 \cdot 1}, a_{2} = \frac{- ( - 3 ) - 1}{2 \cdot 1}

a = \frac{- ( - 3 ) + 1}{2 \cdot 1} : 2

a = \frac{- ( - 3 ) - 1}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

a = 2, a = 1

x^{2} + 15 x = 5 x - 24

25 (x^{2} - 5) + 14 = 10

5 x^{2} - 9 x = - 4

8 1^{2} - 144 y^{2} = 11664

2 x^{2} + 2 x - 6 = 0

What are the solutions to the equation a^2-3a+2=0 ?
The solutions to the equation a^2-3a+2=0 are a=2,a=1
Find the zeros of a^2-3a+2=0
The zeros of a^2-3a+2=0 are a=2,a=1