What are the solutions to the equation (3x-1)^2-49=-13 ?

The solutions to the equation (3x-1)^2-49=-13 are x= 7/3 ,x=-5/3

Find the zeros of (3x-1)^2-49=-13

The zeros of (3x-1)^2-49=-13 are x= 7/3 ,x=-5/3

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(3 x - 1)^{2} - 49 = - 13

x = \frac{7}{3}, x = - \frac{5}{3}

Decimal Notation

x = 2.33333 \dots, x = - 1.66666 \dots

Solution steps

(3 x - 1)^{2} - 49 = - 13

Move

49

to the right side

(3 x - 1)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 1 = 36 : x = \frac{7}{3}

Solve

3 x - 1 = - 36 : x = - \frac{5}{3}

The solutions to the quadratic equation are:

x = \frac{7}{3}, x = - \frac{5}{3}

3 x^{2} + 8 x - 5 = 0

x^{2} + 3 x + 2 = 0

2 x^{2} + (4 a - b) x - 2 ab = 0

3 (3 x - 2)^{2} - 42 = - 36

2 x^{2} - 5 x - 3 = 0

What are the solutions to the equation (3x-1)^2-49=-13 ?
The solutions to the equation (3x-1)^2-49=-13 are x= 7/3 ,x=-5/3
Find the zeros of (3x-1)^2-49=-13
The zeros of (3x-1)^2-49=-13 are x= 7/3 ,x=-5/3