What are the solutions to the equation x^2-2x+13=0 ?

The solutions to the equation x^2-2x+13=0 are x=1+2sqrt(3)i,x=1-2sqrt(3)i

Find the zeros of x^2-2x+13=0

The zeros of x^2-2x+13=0 are x=1+2sqrt(3)i,x=1-2sqrt(3)i

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x^{2} - 2 x + 13 = 0

x = 1 + 23 i, x = 1 - 23 i

Solution steps

x^{2} - 2 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 13 : 43 i

x_{1, 2} = \frac{- ( - 2 ) \pm 4 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 4 3 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 4 3 i}{2 \cdot 1} : 1 + 23 i

x = \frac{- ( - 2 ) - 4 3 i}{2 \cdot 1} : 1 - 23 i

The solutions to the quadratic equation are:

x = 1 + 23 i, x = 1 - 23 i

x^{2} - 5 x + 6 = 0

5 x^{2} + 20 x + 16 = 0

x^{2} - (3 + 5) x + 4 = 0

t^{2} - 2 t = 0

x^{2} + 12 x - 21 = 7 x + 3

What are the solutions to the equation x^2-2x+13=0 ?
The solutions to the equation x^2-2x+13=0 are x=1+2sqrt(3)i,x=1-2sqrt(3)i
Find the zeros of x^2-2x+13=0
The zeros of x^2-2x+13=0 are x=1+2sqrt(3)i,x=1-2sqrt(3)i