What are the solutions to the equation -2x^2+x+8=0 ?

The solutions to the equation -2x^2+x+8=0 are x=-(-1+sqrt(65))/4 ,x=(1+sqrt(65))/4

Find the zeros of -2x^2+x+8=0

The zeros of -2x^2+x+8=0 are x=-(-1+sqrt(65))/4 ,x=(1+sqrt(65))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} + x + 8 = 0

x = - \frac{- 1 + 65}{4}, x = \frac{1 + 65}{4}

Decimal Notation

x = - 1.76556 \dots, x = 2.26556 \dots

Solution steps

- 2 x^{2} + x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) \cdot 8}{2 ( - 2 )}

1^{2} - 4 (- 2) \cdot 8 = 65

x_{1, 2} = \frac{- 1 \pm 65}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 65}{2 ( - 2 )}, x_{2} = \frac{- 1 - 65}{2 ( - 2 )}

x = \frac{- 1 + 65}{2 ( - 2 )} : - \frac{- 1 + 65}{4}

x = \frac{- 1 - 65}{2 ( - 2 )} : \frac{1 + 65}{4}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 65}{4}, x = \frac{1 + 65}{4}

4 x^{2} - x - 14

(- \frac{9}{8})^{2}

- 17 + 6 x \leq - 59

\frac{1}{1 + e ^{0}}

1096

What are the solutions to the equation -2x^2+x+8=0 ?
The solutions to the equation -2x^2+x+8=0 are x=-(-1+sqrt(65))/4 ,x=(1+sqrt(65))/4
Find the zeros of -2x^2+x+8=0
The zeros of -2x^2+x+8=0 are x=-(-1+sqrt(65))/4 ,x=(1+sqrt(65))/4