What are the solutions to the equation 4(3x-8)^2-17=19 ?

The solutions to the equation 4(3x-8)^2-17=19 are x= 11/3 ,x= 5/3

Find the zeros of 4(3x-8)^2-17=19

The zeros of 4(3x-8)^2-17=19 are x= 11/3 ,x= 5/3

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4 (3 x - 8)^{2} - 17 = 19

x = \frac{11}{3}, x = \frac{5}{3}

Decimal Notation

x = 3.66666 \dots, x = 1.66666 \dots

Solution steps

4 (3 x - 8)^{2} - 17 = 19

Move

17

to the right side

4 (3 x - 8)^{2} = 36

Divide both sides by

4

(3 x - 8)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 8 = 9 : x = \frac{11}{3}

Solve

3 x - 8 = - 9 : x = \frac{5}{3}

The solutions to the quadratic equation are:

x = \frac{11}{3}, x = \frac{5}{3}

4 x^{2} + 11 x = 3

5 (x + 3) - 5 (x^{2} - 1) = x^{2} + 7 (3 - x) - 1

8 x^{2} - 128 = 0

3 (x + 1)^{2} - 4 = 5

8 x^{2} - 24 x = 0

What are the solutions to the equation 4(3x-8)^2-17=19 ?
The solutions to the equation 4(3x-8)^2-17=19 are x= 11/3 ,x= 5/3
Find the zeros of 4(3x-8)^2-17=19
The zeros of 4(3x-8)^2-17=19 are x= 11/3 ,x= 5/3