What are the solutions to the equation a^2-4a+4=0 ?

The solutions to the equation a^2-4a+4=0 are a=2

Find the zeros of a^2-4a+4=0

The zeros of a^2-4a+4=0 are a=2

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a^{2} - 4 a + 4 = 0

a = 2

Solution steps

a^{2} - 4 a + 4 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

a_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

a = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

a = 2

The solution to the quadratic equation is:

a = 2

(y + 1) (y + 3) = - 2

4 (3 x - 7)^{2} = 49

x^{2} + 6 x + 4 = 0

12 x^{2} - 52 x + 40 = 0

x, x^{2} + y^{2} - 4 x - 2 y + 25 = 0

What are the solutions to the equation a^2-4a+4=0 ?
The solutions to the equation a^2-4a+4=0 are a=2
Find the zeros of a^2-4a+4=0
The zeros of a^2-4a+4=0 are a=2