What are the solutions to the equation (3x+2)^2+2=3 ?

The solutions to the equation (3x+2)^2+2=3 are x=-1/3 ,x=-1

Find the zeros of (3x+2)^2+2=3

The zeros of (3x+2)^2+2=3 are x=-1/3 ,x=-1

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(3 x + 2)^{2} + 2 = 3

x = - \frac{1}{3}, x = - 1

Decimal Notation

x = - 0.33333 \dots, x = - 1

Solution steps

(3 x + 2)^{2} + 2 = 3

Move

2

to the right side

(3 x + 2)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 2 = 1 : x = - \frac{1}{3}

Solve

3 x + 2 = - 1 : x = - 1

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - 1

x^{2} - 5 x = 9.75

6 n^{2} - 11 = 0

p, \frac{5 x ^{2} - 2 p ^{2}}{x} = \frac{p}{3}

x^{2} - 2 x + x = 0

3 x^{2} + 6 x + d = 0

What are the solutions to the equation (3x+2)^2+2=3 ?
The solutions to the equation (3x+2)^2+2=3 are x=-1/3 ,x=-1
Find the zeros of (3x+2)^2+2=3
The zeros of (3x+2)^2+2=3 are x=-1/3 ,x=-1