What are the solutions to the equation 2^2=1^2+x^2 ?

The solutions to the equation 2^2=1^2+x^2 are x=sqrt(3),x=-sqrt(3)

Find the zeros of 2^2=1^2+x^2

The zeros of 2^2=1^2+x^2 are x=sqrt(3),x=-sqrt(3)

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2^{2} = 1^{2} + x^{2}

x = 3, x = - 3

Decimal Notation

x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

2^{2} = 1^{2} + x^{2}

Switch sides

1^{2} + x^{2} = 2^{2}

Move

1^{2}

to the right side

x^{2} = 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 3, x = - 3

x, f = 2 x^{2} + x y + y^{2} + 100 - z (x + y - 100)

x^{2} - 5 x - 14 = 0

(2 x + 1) (x + 1) = (x + 2) (x - 2) + 3

4 x^{2} + 9 x + 2 = 0

m^{2} - 4 m + 13 = 0

What are the solutions to the equation 2^2=1^2+x^2 ?
The solutions to the equation 2^2=1^2+x^2 are x=sqrt(3),x=-sqrt(3)
Find the zeros of 2^2=1^2+x^2
The zeros of 2^2=1^2+x^2 are x=sqrt(3),x=-sqrt(3)