What are the solutions to the equation -2x^2-x+6=0 ?

The solutions to the equation -2x^2-x+6=0 are x=-2,x= 3/2

Find the zeros of -2x^2-x+6=0

The zeros of -2x^2-x+6=0 are x=-2,x= 3/2

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- 2 x^{2} - x + 6 = 0

x = - 2, x = \frac{3}{2}

Decimal Notation

x = - 2, x = 1.5

Solution steps

- 2 x^{2} - x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 2 ) \cdot 6}{2 ( - 2 )}

(- 1)^{2} - 4 (- 2) \cdot 6 = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 ( - 2 )}, x_{2} = \frac{- ( - 1 ) - 7}{2 ( - 2 )}

x = \frac{- ( - 1 ) + 7}{2 ( - 2 )} : - 2

x = \frac{- ( - 1 ) - 7}{2 ( - 2 )} : \frac{3}{2}

The solutions to the quadratic equation are:

x = - 2, x = \frac{3}{2}

x^{2} + 3 x - 10 = 0

x^{2} - 6 = 10

x^{2} + 9 x - 16 = 9 x

c, a^{2} + b^{2} = c^{2}

x^{2} + 14 x - 5 = 0

What are the solutions to the equation -2x^2-x+6=0 ?
The solutions to the equation -2x^2-x+6=0 are x=-2,x= 3/2
Find the zeros of -2x^2-x+6=0
The zeros of -2x^2-x+6=0 are x=-2,x= 3/2