What are the solutions to the equation x^2+45=14x ?

The solutions to the equation x^2+45=14x are x=9,x=5

Find the zeros of x^2+45=14x

The zeros of x^2+45=14x are x=9,x=5

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x^{2} + 45 = 14 x

x = 9, x = 5

Solution steps

x^{2} + 45 = 14 x

Move

14 x

to the left side

x^{2} + 45 - 14 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 14 x + 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 45}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 45 = 4

x_{1, 2} = \frac{- ( - 14 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 4}{2 \cdot 1}

x = \frac{- ( - 14 ) + 4}{2 \cdot 1} : 9

x = \frac{- ( - 14 ) - 4}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

x = 9, x = 5

x^{2} - x + 1

x^{2} + (x + 2)^{2} = (x + 4)^{2}

x^{2} - 8 x = - 8

25 (5 + 2 x)^{2} + 14 = 30

8 x (x - 1) = 7 x^{2} + 4 x

What are the solutions to the equation x^2+45=14x ?
The solutions to the equation x^2+45=14x are x=9,x=5
Find the zeros of x^2+45=14x
The zeros of x^2+45=14x are x=9,x=5