What are the solutions to the equation s^2+16=0 ?

The solutions to the equation s^2+16=0 are s=4i,s=-4i

Find the zeros of s^2+16=0

The zeros of s^2+16=0 are s=4i,s=-4i

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s^{2} + 16 = 0

s = 4 i, s = - 4 i

Solution steps

s^{2} + 16 = 0

Move

16

to the right side

s^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

s = - 16, s = - - 16

- 16 = 4 i

- - 16 = - 4 i

s = 4 i, s = - 4 i

x^{2} - 5 x = - 20

2 p^{2} = 3 p

\frac{w ^{2}}{- 2} = - 128

2 x^{2} + 4 x = - 1

4 x^{2} + 16 x + 19 = 0

What are the solutions to the equation s^2+16=0 ?
The solutions to the equation s^2+16=0 are s=4i,s=-4i
Find the zeros of s^2+16=0
The zeros of s^2+16=0 are s=4i,s=-4i