What are the solutions to the equation 3x^2+7=301 ?

The solutions to the equation 3x^2+7=301 are x=7sqrt(2),x=-7sqrt(2)

Find the zeros of 3x^2+7=301

The zeros of 3x^2+7=301 are x=7sqrt(2),x=-7sqrt(2)

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3 x^{2} + 7 = 301

x = 72, x = - 72

Decimal Notation

x = 9.89949 \dots, x = - 9.89949 \dots

Solution steps

3 x^{2} + 7 = 301

Move

7

to the right side

3 x^{2} = 294

Divide both sides by

3

x^{2} = 98

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 98, x = - 98

98 = 72

- 98 = - 72

x = 72, x = - 72

x^{2} + 7 x = 68.75

2 x^{2} + 16 x - 5

x^{2} - 6 x + 20 = 0

a^{2} + 8 a - 20 = 0

2 x^{2} + 3 x - 2

What are the solutions to the equation 3x^2+7=301 ?
The solutions to the equation 3x^2+7=301 are x=7sqrt(2),x=-7sqrt(2)
Find the zeros of 3x^2+7=301
The zeros of 3x^2+7=301 are x=7sqrt(2),x=-7sqrt(2)