What are the solutions to the equation x^2+10x=3 ?

The solutions to the equation x^2+10x=3 are x=-5+2sqrt(7),x=-5-2sqrt(7)

Find the zeros of x^2+10x=3

The zeros of x^2+10x=3 are x=-5+2sqrt(7),x=-5-2sqrt(7)

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x^{2} + 10 x = 3

x = - 5 + 27, x = - 5 - 27

Decimal Notation

x = 0.29150 \dots, x = - 10.29150 \dots

Solution steps

x^{2} + 10 x = 3

Move

3

to the left side

x^{2} + 10 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 3) = 47

x_{1, 2} = \frac{- 10 \pm 4 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 4 7}{2 \cdot 1}, x_{2} = \frac{- 10 - 4 7}{2 \cdot 1}

x = \frac{- 10 + 4 7}{2 \cdot 1} : - 5 + 27

x = \frac{- 10 - 4 7}{2 \cdot 1} : - 5 - 27

The solutions to the quadratic equation are:

x = - 5 + 27, x = - 5 - 27

x^{2} - 4 x + 4

x, y^{4} = y^{2} - x^{2}

4 x^{2} = 5 x + 8

(x + 5) (x + 7) = 0

x^{2} = 1 6^{2} + 1 2^{2}

What are the solutions to the equation x^2+10x=3 ?
The solutions to the equation x^2+10x=3 are x=-5+2sqrt(7),x=-5-2sqrt(7)
Find the zeros of x^2+10x=3
The zeros of x^2+10x=3 are x=-5+2sqrt(7),x=-5-2sqrt(7)