What are the solutions to the equation 14n^2-5=33n ?

The solutions to the equation 14n^2-5=33n are n= 5/2 ,n=-1/7

Find the zeros of 14n^2-5=33n

The zeros of 14n^2-5=33n are n= 5/2 ,n=-1/7

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14 n^{2} - 5 = 33 n

n = \frac{5}{2}, n = - \frac{1}{7}

Decimal Notation

n = 2.5, n = - 0.14285 \dots

Solution steps

14 n^{2} - 5 = 33 n

Move

33 n

to the left side

14 n^{2} - 5 - 33 n = 0

Write in the standard form

a x^{2} + b x + c = 0

14 n^{2} - 33 n - 5 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 33 ) \pm ( - 33 ) ^{2} - 4 \cdot 14 ( - 5 )}{2 \cdot 14}

(- 33)^{2} - 4 \cdot 14 (- 5) = 37

n_{1, 2} = \frac{- ( - 33 ) \pm 37}{2 \cdot 14}

Separate the solutions

n_{1} = \frac{- ( - 33 ) + 37}{2 \cdot 14}, n_{2} = \frac{- ( - 33 ) - 37}{2 \cdot 14}

n = \frac{- ( - 33 ) + 37}{2 \cdot 14} : \frac{5}{2}

n = \frac{- ( - 33 ) - 37}{2 \cdot 14} : - \frac{1}{7}

The solutions to the quadratic equation are:

n = \frac{5}{2}, n = - \frac{1}{7}

x^{2} + 5^{2} = 8^{2}

6 x - x^{2} = x^{2} - 2 x

3 s (s - 2) = 12 s

x^{2} + 2 x + 13 = 0

- 3 x^{2} + 9 = 0

What are the solutions to the equation 14n^2-5=33n ?
The solutions to the equation 14n^2-5=33n are n= 5/2 ,n=-1/7
Find the zeros of 14n^2-5=33n
The zeros of 14n^2-5=33n are n= 5/2 ,n=-1/7