What are the solutions to the equation 4(x-9)^2+25=45 ?

The solutions to the equation 4(x-9)^2+25=45 are x=sqrt(5)+9,x=-sqrt(5)+9

Find the zeros of 4(x-9)^2+25=45

The zeros of 4(x-9)^2+25=45 are x=sqrt(5)+9,x=-sqrt(5)+9

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4 (x - 9)^{2} + 25 = 45

x = 5 + 9, x = - 5 + 9

Decimal Notation

x = 11.23606 \dots, x = 6.76393 \dots

Solution steps

4 (x - 9)^{2} + 25 = 45

Move

25

to the right side

4 (x - 9)^{2} = 20

Divide both sides by

4

(x - 9)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 9 = 5 : x = 5 + 9

Solve

x - 9 = - 5 : x = - 5 + 9

The solutions to the quadratic equation are:

x = 5 + 9, x = - 5 + 9

(x + 9)^{2} = - 9

3 n^{2} + 2 n - 1 = - 2 n

3 k^{2} + 2 = 0

0 = 3 x^{2} + 6

x^{2} - 7 x + 15 = 0

What are the solutions to the equation 4(x-9)^2+25=45 ?
The solutions to the equation 4(x-9)^2+25=45 are x=sqrt(5)+9,x=-sqrt(5)+9
Find the zeros of 4(x-9)^2+25=45
The zeros of 4(x-9)^2+25=45 are x=sqrt(5)+9,x=-sqrt(5)+9