What are the solutions to the equation -2(x+2)^2=5 ?

The solutions to the equation -2(x+2)^2=5 are x=isqrt(5/2)-2,x=-isqrt(5/2)-2

Find the zeros of -2(x+2)^2=5

The zeros of -2(x+2)^2=5 are x=isqrt(5/2)-2,x=-isqrt(5/2)-2

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- 2 (x + 2)^{2} = 5

x = i \frac{5}{2} - 2, x = - i \frac{5}{2} - 2

Solution steps

- 2 (x + 2)^{2} = 5

Divide both sides by

- 2

(x + 2)^{2} = - \frac{5}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = - \frac{5}{2} : x = i \frac{5}{2} - 2

Solve

x + 2 = - - \frac{5}{2} : x = - i \frac{5}{2} - 2

The solutions to the quadratic equation are:

x = i \frac{5}{2} - 2, x = - i \frac{5}{2} - 2

(x^{2} - 2) = 0

x^{2} = 175

4 x^{2} + 20 x = - 25

x^{2} + 1 = - 2 x

9 n^{2} - 3 n - 8 = - 10

What are the solutions to the equation -2(x+2)^2=5 ?
The solutions to the equation -2(x+2)^2=5 are x=isqrt(5/2)-2,x=-isqrt(5/2)-2
Find the zeros of -2(x+2)^2=5
The zeros of -2(x+2)^2=5 are x=isqrt(5/2)-2,x=-isqrt(5/2)-2