What is 4x+8>=-12\lor 3x+8>11 ?

The solution to 4x+8>=-12\lor 3x+8>11 is x>=-5

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4x+8>=-12\lor 3x+8>11

4 x + 8 \geq - 12 or 3 x + 8 > 11

x \geq - 5

Interval Notation

[- 5, \infty)

Solution steps

4 x + 8 \geq - 12 or 3 x + 8 > 11

4 x + 8 \geq - 12 : x \geq - 5

3 x + 8 > 11 : x > 1

Combine the intervals

x \geq - 5 or x > 1

Merge Overlapping Intervals

x \geq - 5

5 x^{2} - 70 x = - 230

45 x - 0.9 x^{2} = \frac{( 562.5 )}{2}

\frac{( 1 \cdot 1 0 ^{0} )}{2 \cdot 1 0 ^{1}}

x^{2} - 2 x + \frac{1}{4} = 0

1 0^{4 l o g_{10} (5)}