What are the solutions to the equation 2a^2+8a+10=a^2 ?

The solutions to the equation 2a^2+8a+10=a^2 are a=-4+sqrt(6),a=-4-sqrt(6)

Find the zeros of 2a^2+8a+10=a^2

The zeros of 2a^2+8a+10=a^2 are a=-4+sqrt(6),a=-4-sqrt(6)

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2 a^{2} + 8 a + 10 = a^{2}

a = - 4 + 6, a = - 4 - 6

Decimal Notation

a = - 1.55051 \dots, a = - 6.44948 \dots

Solution steps

2 a^{2} + 8 a + 10 = a^{2}

Move

a^{2}

to the left side

a^{2} + 8 a + 10 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 10 = 26

a_{1, 2} = \frac{- 8 \pm 2 6}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 8 + 2 6}{2 \cdot 1}, a_{2} = \frac{- 8 - 2 6}{2 \cdot 1}

a = \frac{- 8 + 2 6}{2 \cdot 1} : - 4 + 6

a = \frac{- 8 - 2 6}{2 \cdot 1} : - 4 - 6

The solutions to the quadratic equation are:

a = - 4 + 6, a = - 4 - 6

(4 q + 5) (q - 5) = 0

4 y^{2} - 12 = 0

x^{2} + x + c = 0

\frac{r ^{2}}{- 7} = - 28

x^{2} + 10 x + 28 = 0

What are the solutions to the equation 2a^2+8a+10=a^2 ?
The solutions to the equation 2a^2+8a+10=a^2 are a=-4+sqrt(6),a=-4-sqrt(6)
Find the zeros of 2a^2+8a+10=a^2
The zeros of 2a^2+8a+10=a^2 are a=-4+sqrt(6),a=-4-sqrt(6)