What are the solutions to the equation y^2-2y+8=0 ?

The solutions to the equation y^2-2y+8=0 are y=1+sqrt(7)i,y=1-sqrt(7)i

Find the zeros of y^2-2y+8=0

The zeros of y^2-2y+8=0 are y=1+sqrt(7)i,y=1-sqrt(7)i

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y^{2} - 2 y + 8 = 0

y = 1 + 7 i, y = 1 - 7 i

Solution steps

y^{2} - 2 y + 8 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 8 : 27 i

y_{1, 2} = \frac{- ( - 2 ) \pm 2 7 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 2 ) + 2 7 i}{2 \cdot 1}, y_{2} = \frac{- ( - 2 ) - 2 7 i}{2 \cdot 1}

y = \frac{- ( - 2 ) + 2 7 i}{2 \cdot 1} : 1 + 7 i

y = \frac{- ( - 2 ) - 2 7 i}{2 \cdot 1} : 1 - 7 i

The solutions to the quadratic equation are:

y = 1 + 7 i, y = 1 - 7 i

100 x - x^{2} = 1612.5

20 x^{2} + 10 x = 0

2 v^{2} + 4 v = 6

10 x^{2} + 7 x + 1 = 0

x^{2} + 5 x - 14 = 0

What are the solutions to the equation y^2-2y+8=0 ?
The solutions to the equation y^2-2y+8=0 are y=1+sqrt(7)i,y=1-sqrt(7)i
Find the zeros of y^2-2y+8=0
The zeros of y^2-2y+8=0 are y=1+sqrt(7)i,y=1-sqrt(7)i