What are the solutions to the equation 25m^2-17=-1 ?

The solutions to the equation 25m^2-17=-1 are m= 4/5 ,m=-4/5

Find the zeros of 25m^2-17=-1

The zeros of 25m^2-17=-1 are m= 4/5 ,m=-4/5

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25 m^{2} - 17 = - 1

m = \frac{4}{5}, m = - \frac{4}{5}

Decimal Notation

m = 0.8, m = - 0.8

Solution steps

25 m^{2} - 17 = - 1

Move

17

to the right side

25 m^{2} = 16

Divide both sides by

25

m^{2} = \frac{16}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = \frac{16}{25}, m = - \frac{16}{25}

\frac{16}{25} = \frac{4}{5}

- \frac{16}{25} = - \frac{4}{5}

m = \frac{4}{5}, m = - \frac{4}{5}

x (x + 2) = 48

x, 4 x^{2} - 4 x y + y^{2} + 32 x + 34 y + 89 = 0

5 x^{2} + 100 = 0

x (2 x - 5) = 0

(x - 2)^{2} = - 3 x + 6

What are the solutions to the equation 25m^2-17=-1 ?
The solutions to the equation 25m^2-17=-1 are m= 4/5 ,m=-4/5
Find the zeros of 25m^2-17=-1
The zeros of 25m^2-17=-1 are m= 4/5 ,m=-4/5