What are the solutions to the equation m^2-2m-15=0 ?

The solutions to the equation m^2-2m-15=0 are m=5,m=-3

Find the zeros of m^2-2m-15=0

The zeros of m^2-2m-15=0 are m=5,m=-3

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m^{2} - 2 m - 15 = 0

m = 5, m = - 3

Solution steps

m^{2} - 2 m - 15 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 15) = 8

m_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 1}, m_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 1}

m = \frac{- ( - 2 ) + 8}{2 \cdot 1} : 5

m = \frac{- ( - 2 ) - 8}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

m = 5, m = - 3

5 x^{2} - 50 x = 0

a^{2} + 2 a - 35 = 0

x^{2} - 2 x + 184 = 2 x

6 x^{2} - 48 x - 54 = 0

2 x^{2} + 50 x = 0

What are the solutions to the equation m^2-2m-15=0 ?
The solutions to the equation m^2-2m-15=0 are m=5,m=-3
Find the zeros of m^2-2m-15=0
The zeros of m^2-2m-15=0 are m=5,m=-3