What are the solutions to the equation x^2+26x=27 ?

The solutions to the equation x^2+26x=27 are x=1,x=-27

Find the zeros of x^2+26x=27

The zeros of x^2+26x=27 are x=1,x=-27

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 26 x = 27

x = 1, x = - 27

Solution steps

x^{2} + 26 x = 27

Move

27

to the left side

x^{2} + 26 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 \cdot 1 \cdot ( - 27 )}{2 \cdot 1}

2 6^{2} - 4 \cdot 1 \cdot (- 27) = 28

x_{1, 2} = \frac{- 26 \pm 28}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 26 + 28}{2 \cdot 1}, x_{2} = \frac{- 26 - 28}{2 \cdot 1}

x = \frac{- 26 + 28}{2 \cdot 1} : 1

x = \frac{- 26 - 28}{2 \cdot 1} : - 27

The solutions to the quadratic equation are:

x = 1, x = - 27

(5 x - 3)^{2} = 64

a^{2} - 8 a - 6 = 0

- 3 x^{2} - x + 1 = 0

x^{2} + x - 306 = 0

x, x^{2} + y^{2} + z^{2} = 2

What are the solutions to the equation x^2+26x=27 ?
The solutions to the equation x^2+26x=27 are x=1,x=-27
Find the zeros of x^2+26x=27
The zeros of x^2+26x=27 are x=1,x=-27