What are the solutions to the equation 2v^2+15v+17=0 ?

The solutions to the equation 2v^2+15v+17=0 are v=(-15+sqrt(89))/4 ,v=(-15-sqrt(89))/4

Find the zeros of 2v^2+15v+17=0

The zeros of 2v^2+15v+17=0 are v=(-15+sqrt(89))/4 ,v=(-15-sqrt(89))/4

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2 v^{2} + 15 v + 17 = 0

v = \frac{- 15 + 89}{4}, v = \frac{- 15 - 89}{4}

Decimal Notation

v = - 1.39150 \dots, v = - 6.10849 \dots

Solution steps

2 v^{2} + 15 v + 17 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 2 \cdot 17}{2 \cdot 2}

1 5^{2} - 4 \cdot 2 \cdot 17 = 89

v_{1, 2} = \frac{- 15 \pm 89}{2 \cdot 2}

Separate the solutions

v_{1} = \frac{- 15 + 89}{2 \cdot 2}, v_{2} = \frac{- 15 - 89}{2 \cdot 2}

v = \frac{- 15 + 89}{2 \cdot 2} : \frac{- 15 + 89}{4}

v = \frac{- 15 - 89}{2 \cdot 2} : \frac{- 15 - 89}{4}

The solutions to the quadratic equation are:

v = \frac{- 15 + 89}{4}, v = \frac{- 15 - 89}{4}

y^{2} = 5

x^{2} = 2 x + 5

A (x) = - (x - 25)^{2} + 625

x^{2} + x - 7

x^{2} - 20 x

What are the solutions to the equation 2v^2+15v+17=0 ?
The solutions to the equation 2v^2+15v+17=0 are v=(-15+sqrt(89))/4 ,v=(-15-sqrt(89))/4
Find the zeros of 2v^2+15v+17=0
The zeros of 2v^2+15v+17=0 are v=(-15+sqrt(89))/4 ,v=(-15-sqrt(89))/4