What are the solutions to the equation 12x^2-6=0 ?

The solutions to the equation 12x^2-6=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

Find the zeros of 12x^2-6=0

The zeros of 12x^2-6=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

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12 x^{2} - 6 = 0

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.70710 \dots, x = - 0.70710 \dots

Solution steps

12 x^{2} - 6 = 0

Move

6

to the right side

12 x^{2} = 6

Divide both sides by

12

x^{2} = \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{2}, x = - \frac{1}{2}

\frac{1}{2} = \frac{1}{2}

- \frac{1}{2} = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

x, 2 x^{2} - 2 y^{2} - 4 x + 8 y = 6

\frac{x ^{2} - 3}{2} - \frac{x + 2}{4} = 5

y, 9 y^{2} = 4 x^{3}

3 x^{2} + 2 x = 2

x^{2} - 4 x - 57 = - 2 x - 9

What are the solutions to the equation 12x^2-6=0 ?
The solutions to the equation 12x^2-6=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))
Find the zeros of 12x^2-6=0
The zeros of 12x^2-6=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))