What are the solutions to the equation x^2+2x+1=3x+3 ?

The solutions to the equation x^2+2x+1=3x+3 are x=2,x=-1

Find the zeros of x^2+2x+1=3x+3

The zeros of x^2+2x+1=3x+3 are x=2,x=-1

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x^{2} + 2 x + 1 = 3 x + 3

x = 2, x = - 1

Solution steps

x^{2} + 2 x + 1 = 3 x + 3

Move

3

to the left side

x^{2} + 2 x - 2 = 3 x

Move

3 x

to the left side

x^{2} - x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 2) = 3

x_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 1}

x = \frac{- ( - 1 ) + 3}{2 \cdot 1} : 2

x = \frac{- ( - 1 ) - 3}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 2, x = - 1

x^{2} - 5 x + 6 = 0

5 d^{2} + 15 d + 5 = - 6

2 x^{2} + 4 x - 5

- 8 x^{2} + 4 x = - 5

6 x^{2} + 24 x - 564 = 0

What are the solutions to the equation x^2+2x+1=3x+3 ?
The solutions to the equation x^2+2x+1=3x+3 are x=2,x=-1
Find the zeros of x^2+2x+1=3x+3
The zeros of x^2+2x+1=3x+3 are x=2,x=-1