What are the solutions to the equation x^2+1=4x^2 ?

The solutions to the equation x^2+1=4x^2 are x= 1/(sqrt(3)),x=-1/(sqrt(3))

Find the zeros of x^2+1=4x^2

The zeros of x^2+1=4x^2 are x= 1/(sqrt(3)),x=-1/(sqrt(3))

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x^{2} + 1 = 4 x^{2}

x = \frac{1}{3}, x = - \frac{1}{3}

Decimal Notation

x = 0.57735 \dots, x = - 0.57735 \dots

Solution steps

x^{2} + 1 = 4 x^{2}

Move

1

to the right side

x^{2} = 4 x^{2} - 1

Move

4 x^{2}

to the left side

- 3 x^{2} = - 1

Divide both sides by

- 3

x^{2} = \frac{1}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{3}, x = - \frac{1}{3}

\frac{1}{3} = \frac{1}{3}

- \frac{1}{3} = - \frac{1}{3}

x = \frac{1}{3}, x = - \frac{1}{3}

- 15 x = 45 x^{2}

x, 5 x^{2} + 5 y^{2} + 10 x - 10 y + 20 = 0

m^{2} = 0

- x^{2} = - 4

4 x^{2} + 24 x - 5 = 19

What are the solutions to the equation x^2+1=4x^2 ?
The solutions to the equation x^2+1=4x^2 are x= 1/(sqrt(3)),x=-1/(sqrt(3))
Find the zeros of x^2+1=4x^2
The zeros of x^2+1=4x^2 are x= 1/(sqrt(3)),x=-1/(sqrt(3))