What are the solutions to the equation 3a^2-10a+2=0 ?

The solutions to the equation 3a^2-10a+2=0 are a=(5+sqrt(19))/3 ,a=(5-sqrt(19))/3

Find the zeros of 3a^2-10a+2=0

The zeros of 3a^2-10a+2=0 are a=(5+sqrt(19))/3 ,a=(5-sqrt(19))/3

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3 a^{2} - 10 a + 2 = 0

a = \frac{5 + 19}{3}, a = \frac{5 - 19}{3}

Decimal Notation

a = 3.11963 \dots, a = 0.21370 \dots

Solution steps

3 a^{2} - 10 a + 2 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

(- 10)^{2} - 4 \cdot 3 \cdot 2 = 219

a_{1, 2} = \frac{- ( - 10 ) \pm 2 19}{2 \cdot 3}

Separate the solutions

a_{1} = \frac{- ( - 10 ) + 2 19}{2 \cdot 3}, a_{2} = \frac{- ( - 10 ) - 2 19}{2 \cdot 3}

a = \frac{- ( - 10 ) + 2 19}{2 \cdot 3} : \frac{5 + 19}{3}

a = \frac{- ( - 10 ) - 2 19}{2 \cdot 3} : \frac{5 - 19}{3}

The solutions to the quadratic equation are:

a = \frac{5 + 19}{3}, a = \frac{5 - 19}{3}

3 x^{2} + 30 x + 75 = 0

x^{2} - 9 x = - 14

x^{2} + 5 x - 20 = 4

x^{2} + x^{2} = 1

x^{2} + 14 = 50

What are the solutions to the equation 3a^2-10a+2=0 ?
The solutions to the equation 3a^2-10a+2=0 are a=(5+sqrt(19))/3 ,a=(5-sqrt(19))/3
Find the zeros of 3a^2-10a+2=0
The zeros of 3a^2-10a+2=0 are a=(5+sqrt(19))/3 ,a=(5-sqrt(19))/3