What are the solutions to the equation (x+2)(x+4)=6x^2 ?

The solutions to the equation (x+2)(x+4)=6x^2 are x=-4/5 ,x=2

Find the zeros of (x+2)(x+4)=6x^2

The zeros of (x+2)(x+4)=6x^2 are x=-4/5 ,x=2

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(x + 2) (x + 4) = 6 x^{2}

x = - \frac{4}{5}, x = 2

Decimal Notation

x = - 0.8, x = 2

Solution steps

(x + 2) (x + 4) = 6 x^{2}

Expand

(x + 2) (x + 4) : x^{2} + 6 x + 8

x^{2} + 6 x + 8 = 6 x^{2}

Move

6 x^{2}

to the left side

- 5 x^{2} + 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 5 ) \cdot 8}{2 ( - 5 )}

6^{2} - 4 (- 5) \cdot 8 = 14

x_{1, 2} = \frac{- 6 \pm 14}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 6 + 14}{2 ( - 5 )}, x_{2} = \frac{- 6 - 14}{2 ( - 5 )}

x = \frac{- 6 + 14}{2 ( - 5 )} : - \frac{4}{5}

x = \frac{- 6 - 14}{2 ( - 5 )} : 2

The solutions to the quadratic equation are:

x = - \frac{4}{5}, x = 2

2 x^{2} + 29 = 15 x

4 k^{2} - 1 = 63

5 x^{2} - 9 = 6

m, F = G \frac{mm}{r ^{2}}

x^{2} - x - 110 = 0

What are the solutions to the equation (x+2)(x+4)=6x^2 ?
The solutions to the equation (x+2)(x+4)=6x^2 are x=-4/5 ,x=2
Find the zeros of (x+2)(x+4)=6x^2
The zeros of (x+2)(x+4)=6x^2 are x=-4/5 ,x=2