What are the solutions to the equation x^2-11x+31=0 ?

The solutions to the equation x^2-11x+31=0 are x= 11/2+i(sqrt(3))/2 ,x= 11/2-i(sqrt(3))/2

Find the zeros of x^2-11x+31=0

The zeros of x^2-11x+31=0 are x= 11/2+i(sqrt(3))/2 ,x= 11/2-i(sqrt(3))/2

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x^{2} - 11 x + 31 = 0

x = \frac{11}{2} + i \frac{3}{2}, x = \frac{11}{2} - i \frac{3}{2}

Solution steps

x^{2} - 11 x + 31 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 31}{2 \cdot 1}

Simplify

(- 11)^{2} - 4 \cdot 1 \cdot 31 : 3 i

x_{1, 2} = \frac{- ( - 11 ) \pm 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 3 i}{2 \cdot 1}

x = \frac{- ( - 11 ) + 3 i}{2 \cdot 1} : \frac{11}{2} + i \frac{3}{2}

x = \frac{- ( - 11 ) - 3 i}{2 \cdot 1} : \frac{11}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{11}{2} + i \frac{3}{2}, x = \frac{11}{2} - i \frac{3}{2}

3 + 4 + 6 i

\frac{15}{- 5 i}

\frac{3}{5} + \frac{2}{3}

0.5 (6 x + 4) = 3 x + 4

\frac{x}{4} = \frac{x}{5} - 12

What are the solutions to the equation x^2-11x+31=0 ?
The solutions to the equation x^2-11x+31=0 are x= 11/2+i(sqrt(3))/2 ,x= 11/2-i(sqrt(3))/2
Find the zeros of x^2-11x+31=0
The zeros of x^2-11x+31=0 are x= 11/2+i(sqrt(3))/2 ,x= 11/2-i(sqrt(3))/2