What are the solutions to the equation completesquare x^2+2x-4 ?

The solutions to the equation completesquare x^2+2x-4 are (x+1)^2-5

Find the zeros of completesquare x^2+2x-4

The zeros of completesquare x^2+2x-4 are (x+1)^2-5

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complete the square

x^{2} + 2 x - 4

(x + 1)^{2} - 5

Solution steps

x^{2} + 2 x - 4

Write

x^{2} + 2 x - 4

in the form:

x^{2} + 2 a x + a^{2}

2 a = 2 : a = 1

Add and subtract

1^{2}

x^{2} + 2 x - 4 + 1^{2} - 1^{2}

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} + 2 x + 1^{2} = (x + 1)^{2}

(x + 1)^{2} - 4 - 1^{2}

Simplify

(x + 1)^{2} - 5

x^{2} + 2 x + 3

9 (5 - 2 x)^{2} - 25 = - 21

3 x^{2} - 18 x - 48 = 0

\frac{1}{2} u^{2} + \frac{3}{4} u = - \frac{1}{5}

x + x^{2} = 42

What are the solutions to the equation completesquare x^2+2x-4 ?
The solutions to the equation completesquare x^2+2x-4 are (x+1)^2-5
Find the zeros of completesquare x^2+2x-4
The zeros of completesquare x^2+2x-4 are (x+1)^2-5